What are the solutions to the equation factor y^2+2y-8=0 ?

The solutions to the equation factor y^2+2y-8=0 are y=2,y=-4

Find the zeros of factor y^2+2y-8=0

The zeros of factor y^2+2y-8=0 are y=2,y=-4

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y^{2} + 2 y - 8 = 0

y = 2, y = - 4

Solution steps

y^{2} + 2 y - 8 = 0

Factor

y^{2} + 2 y - 8 : (y - 2) (y + 4)

(y - 2) (y + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y - 2 = 0 or y + 4 = 0

Solve

y - 2 = 0 : y = 2

Solve

y + 4 = 0 : y = - 4

The solutions to the quadratic equation are:

y = 2, y = - 4

(n + 2) (n - 4) = 27

6 - 3 y - y^{2} = 6

2 p^{2} - 11 = 61

3 x^{2} + 16 x - 2 = 0

3 v^{2} - 27 = 0

What are the solutions to the equation factor y^2+2y-8=0 ?
The solutions to the equation factor y^2+2y-8=0 are y=2,y=-4
Find the zeros of factor y^2+2y-8=0
The zeros of factor y^2+2y-8=0 are y=2,y=-4