What are the solutions to the equation 6-3y-y^2=6 ?

The solutions to the equation 6-3y-y^2=6 are y=-3,y=0

Find the zeros of 6-3y-y^2=6

The zeros of 6-3y-y^2=6 are y=-3,y=0

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6 - 3 y - y^{2} = 6

y = - 3, y = 0

Solution steps

6 - 3 y - y^{2} = 6

Move

6

to the left side

- y^{2} - 3 y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

(- 3)^{2} - 4 (- 1) \cdot 0 = 3

y_{1, 2} = \frac{- ( - 3 ) \pm 3}{2 ( - 1 )}

Separate the solutions

y_{1} = \frac{- ( - 3 ) + 3}{2 ( - 1 )}, y_{2} = \frac{- ( - 3 ) - 3}{2 ( - 1 )}

y = \frac{- ( - 3 ) + 3}{2 ( - 1 )} : - 3

y = \frac{- ( - 3 ) - 3}{2 ( - 1 )} : 0

The solutions to the quadratic equation are:

y = - 3, y = 0

2 p^{2} - 11 = 61

3 x^{2} + 16 x - 2 = 0

3 v^{2} - 27 = 0

y, x^{2} - x y + \frac{1}{2} y^{2} = 3

(3 x - 6)^{2} = - 48

What are the solutions to the equation 6-3y-y^2=6 ?
The solutions to the equation 6-3y-y^2=6 are y=-3,y=0
Find the zeros of 6-3y-y^2=6
The zeros of 6-3y-y^2=6 are y=-3,y=0