What are the solutions to the equation (3x-6)^2=-48 ?

The solutions to the equation (3x-6)^2=-48 are x=2+i(4sqrt(3))/3 ,x=2-i(4sqrt(3))/3

Find the zeros of (3x-6)^2=-48

The zeros of (3x-6)^2=-48 are x=2+i(4sqrt(3))/3 ,x=2-i(4sqrt(3))/3

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(3 x - 6)^{2} = - 48

x = 2 + i \frac{4 3}{3}, x = 2 - i \frac{4 3}{3}

Solution steps

(3 x - 6)^{2} = - 48

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x - 6 = - 48 : x = 2 + i \frac{4 3}{3}

Solve

3 x - 6 = - - 48 : x = 2 - i \frac{4 3}{3}

The solutions to the quadratic equation are:

x = 2 + i \frac{4 3}{3}, x = 2 - i \frac{4 3}{3}

3 x^{2} = 289

y^{2} + 9 y + 2 = 8 y + 58

x, 3 x^{2} - 5 x - 1 = 0

4 x^{2} = - 2 x + 4

3 x^{2} - (x + 3)^{2} = x^{2} - 17

What are the solutions to the equation (3x-6)^2=-48 ?
The solutions to the equation (3x-6)^2=-48 are x=2+i(4sqrt(3))/3 ,x=2-i(4sqrt(3))/3
Find the zeros of (3x-6)^2=-48
The zeros of (3x-6)^2=-48 are x=2+i(4sqrt(3))/3 ,x=2-i(4sqrt(3))/3