What are the solutions to the equation 8b-24b^2=0 ?

The solutions to the equation 8b-24b^2=0 are b=0,b= 1/3

Find the zeros of 8b-24b^2=0

The zeros of 8b-24b^2=0 are b=0,b= 1/3

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8 b - 24 b^{2} = 0

b = 0, b = \frac{1}{3}

Decimal

b = 0, b = 0.33333 \dots

Solution steps

8 b - 24 b^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 24 b^{2} + 8 b = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 24 ) \cdot 0}{2 ( - 24 )}

8^{2} - 4 (- 24) \cdot 0 = 8

b_{1, 2} = \frac{- 8 \pm 8}{2 ( - 24 )}

Separate the solutions

b_{1} = \frac{- 8 + 8}{2 ( - 24 )}, b_{2} = \frac{- 8 - 8}{2 ( - 24 )}

b = \frac{- 8 + 8}{2 ( - 24 )} : 0

b = \frac{- 8 - 8}{2 ( - 24 )} : \frac{1}{3}

The solutions to the quadratic equation are:

b = 0, b = \frac{1}{3}

x^{2} - 20 x + 36 = - 7 x

y, x^{2} - x y + y^{2} = 5 x + 6 y - 13

25 x^{2} - 25 x = - 6

y, x^{2} + 4 x y + 16 y^{2} = 27

(x - 1)^{2} = - (x + 1)^{2} + 4

What are the solutions to the equation 8b-24b^2=0 ?
The solutions to the equation 8b-24b^2=0 are b=0,b= 1/3
Find the zeros of 8b-24b^2=0
The zeros of 8b-24b^2=0 are b=0,b= 1/3