What are the solutions to the equation 3x^2-18x+24=-2 ?

The solutions to the equation 3x^2-18x+24=-2 are x=(9+sqrt(3))/3 ,x=(9-sqrt(3))/3

Find the zeros of 3x^2-18x+24=-2

The zeros of 3x^2-18x+24=-2 are x=(9+sqrt(3))/3 ,x=(9-sqrt(3))/3

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3 x^{2} - 18 x + 24 = - 2

x = \frac{9 + 3}{3}, x = \frac{9 - 3}{3}

Decimal Notation

x = 3.57735 \dots, x = 2.42264 \dots

Solution steps

3 x^{2} - 18 x + 24 = - 2

Move

2

to the left side

3 x^{2} - 18 x + 26 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 3 \cdot 26}{2 \cdot 3}

(- 18)^{2} - 4 \cdot 3 \cdot 26 = 23

x_{1, 2} = \frac{- ( - 18 ) \pm 2 3}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 2 3}{2 \cdot 3}, x_{2} = \frac{- ( - 18 ) - 2 3}{2 \cdot 3}

x = \frac{- ( - 18 ) + 2 3}{2 \cdot 3} : \frac{9 + 3}{3}

x = \frac{- ( - 18 ) - 2 3}{2 \cdot 3} : \frac{9 - 3}{3}

The solutions to the quadratic equation are:

x = \frac{9 + 3}{3}, x = \frac{9 - 3}{3}

3 x^{2} - 4 x - 4 = 0

x^{2} - 19 x - 90 = 0

25 π = π (x + 3)^{2}

4 x^{2} - 32 x = - 71

- 4 = x^{2} - 3 x - 4

What are the solutions to the equation 3x^2-18x+24=-2 ?
The solutions to the equation 3x^2-18x+24=-2 are x=(9+sqrt(3))/3 ,x=(9-sqrt(3))/3
Find the zeros of 3x^2-18x+24=-2
The zeros of 3x^2-18x+24=-2 are x=(9+sqrt(3))/3 ,x=(9-sqrt(3))/3