What are the solutions to the equation 25pi=pi(x+3)^2 ?

The solutions to the equation 25pi=pi(x+3)^2 are x=-8,x=2

Find the zeros of 25pi=pi(x+3)^2

The zeros of 25pi=pi(x+3)^2 are x=-8,x=2

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25 π = π (x + 3)^{2}

x = - 8, x = 2

Solution steps

25 π = π (x + 3)^{2}

Move

π (x + 3)^{2}

to the left side

25 π - π (x + 3)^{2} = 0

Factor

25 π - π (x + 3)^{2} : - π (x + 8) (x - 2)

- π (x + 8) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 8 = 0 or x - 2 = 0

Solve

x + 8 = 0 : x = - 8

Solve

x - 2 = 0 : x = 2

The solutions to the quadratic equation are:

x = - 8, x = 2

4 x^{2} - 32 x = - 71

- 4 = x^{2} - 3 x - 4

3 x^{2} + 16 x = 3

m^{2} - 2 m + 3

x^{2} + 4 x = - 5

What are the solutions to the equation 25pi=pi(x+3)^2 ?
The solutions to the equation 25pi=pi(x+3)^2 are x=-8,x=2
Find the zeros of 25pi=pi(x+3)^2
The zeros of 25pi=pi(x+3)^2 are x=-8,x=2