What are the solutions to the equation 3x^2+16x=3 ?

The solutions to the equation 3x^2+16x=3 are x=(-8+sqrt(73))/3 ,x=-(8+sqrt(73))/3

Find the zeros of 3x^2+16x=3

The zeros of 3x^2+16x=3 are x=(-8+sqrt(73))/3 ,x=-(8+sqrt(73))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} + 16 x = 3

x = \frac{- 8 + 73}{3}, x = - \frac{8 + 73}{3}

Decimal

x = 0.18133 \dots, x = - 5.51466 \dots

Solution steps

3 x^{2} + 16 x = 3

Move

3

to the left side

3 x^{2} + 16 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 3 ( - 3 )}{2 \cdot 3}

1 6^{2} - 4 \cdot 3 (- 3) = 273

x_{1, 2} = \frac{- 16 \pm 2 73}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 16 + 2 73}{2 \cdot 3}, x_{2} = \frac{- 16 - 2 73}{2 \cdot 3}

x = \frac{- 16 + 2 73}{2 \cdot 3} : \frac{- 8 + 73}{3}

x = \frac{- 16 - 2 73}{2 \cdot 3} : - \frac{8 + 73}{3}

The solutions to the quadratic equation are:

x = \frac{- 8 + 73}{3}, x = - \frac{8 + 73}{3}

m^{2} - 2 m + 3

x^{2} + 4 x = - 5

4 t^{2} - 9 t + 2 = 0

a, (a + b)^{3} = a^{3} + b^{3}

x, x^{2} - 5 k x - 50 k^{2} = 0

What are the solutions to the equation 3x^2+16x=3 ?
The solutions to the equation 3x^2+16x=3 are x=(-8+sqrt(73))/3 ,x=-(8+sqrt(73))/3
Find the zeros of 3x^2+16x=3
The zeros of 3x^2+16x=3 are x=(-8+sqrt(73))/3 ,x=-(8+sqrt(73))/3