What is the answer to solvefor y,2x+2xy=2y+x^2 ?

The answer to solvefor y,2x+2xy=2y+x^2 is y=(x^2-2x)/(2(-1+x));\quad x\ne 1

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solvefor y,2x+2xy=2y+x^2

solve for

y, 2 x + 2 x y = 2 y + x^{2}

y = \frac{x ^{2} - 2 x}{2 ( - 1 + x )}; x \neq = 1

Solution steps

2 x + 2 x y = 2 y + x^{2}

Move

2 x

to the right side

2 x y = 2 y + x^{2} - 2 x

Move

2 y

to the left side

2 x y - 2 y = x^{2} - 2 x

Factor

2 x y - 2 y : 2 y (x - 1)

2 y (x - 1) = x^{2} - 2 x

Divide both sides by

2 (x - 1); x \neq = 1

y = \frac{x ^{2} - 2 x}{2 ( - 1 + x )}; x \neq = 1

x, x^{2} y + 3 x y^{3} - x = 3

9 x^{2} - 4 x = 1

9 u^{2} - u - 6534 = 0

y, x^{2} = \frac{1}{y + 4}

h^{2} + 400 h - 125000 = 0

What is the answer to solvefor y,2x+2xy=2y+x^2 ?
The answer to solvefor y,2x+2xy=2y+x^2 is y=(x^2-2x)/(2(-1+x));\quad x\ne 1