What are the solutions to the equation (2x-4)^2=9 ?

The solutions to the equation (2x-4)^2=9 are x= 7/2 ,x= 1/2

Find the zeros of (2x-4)^2=9

The zeros of (2x-4)^2=9 are x= 7/2 ,x= 1/2

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(2 x - 4)^{2} = 9

x = \frac{7}{2}, x = \frac{1}{2}

Decimal Notation

x = 3.5, x = 0.5

Solution steps

(2 x - 4)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 4 = 9 : x = \frac{7}{2}

Solve

2 x - 4 = - 9 : x = \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{7}{2}, x = \frac{1}{2}

x^{2} - 4 = - 7

25 x^{2} - 4 = 0

z^{2} + 4 z

x^{2} + (\frac{4 - x}{2})^{2} = 16

3 x^{2} = 81

What are the solutions to the equation (2x-4)^2=9 ?
The solutions to the equation (2x-4)^2=9 are x= 7/2 ,x= 1/2
Find the zeros of (2x-4)^2=9
The zeros of (2x-4)^2=9 are x= 7/2 ,x= 1/2