What are the solutions to the equation factor 25x^2-4=0 ?

The solutions to the equation factor 25x^2-4=0 are x=-2/5 ,x= 2/5

Find the zeros of factor 25x^2-4=0

The zeros of factor 25x^2-4=0 are x=-2/5 ,x= 2/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

25 x^{2} - 4 = 0

x = - \frac{2}{5}, x = \frac{2}{5}

Decimal Notation

x = - 0.4, x = 0.4

Solution steps

25 x^{2} - 4 = 0

Factor

25 x^{2} - 4 : (5 x + 2) (5 x - 2)

(5 x + 2) (5 x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

5 x + 2 = 0 or 5 x - 2 = 0

Solve

5 x + 2 = 0 : x = - \frac{2}{5}

Solve

5 x - 2 = 0 : x = \frac{2}{5}

The solutions to the quadratic equation are:

x = - \frac{2}{5}, x = \frac{2}{5}

z^{2} + 4 z

x^{2} + (\frac{4 - x}{2})^{2} = 16

3 x^{2} = 81

m p^{2} + 2 m + n p^{2} = 2 n

- 3 x^{2} + 49 x = - 5 x + 183

What are the solutions to the equation factor 25x^2-4=0 ?
The solutions to the equation factor 25x^2-4=0 are x=-2/5 ,x= 2/5
Find the zeros of factor 25x^2-4=0
The zeros of factor 25x^2-4=0 are x=-2/5 ,x= 2/5