What are the solutions to the equation -3x^2+49x=-5x+183 ?

The solutions to the equation -3x^2+49x=-5x+183 are x=9-2sqrt(5),x=9+2sqrt(5)

Find the zeros of -3x^2+49x=-5x+183

The zeros of -3x^2+49x=-5x+183 are x=9-2sqrt(5),x=9+2sqrt(5)

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- 3 x^{2} + 49 x = - 5 x + 183

x = 9 - 25, x = 9 + 25

Decimal Notation

x = 4.52786 \dots, x = 13.47213 \dots

Solution steps

- 3 x^{2} + 49 x = - 5 x + 183

Move

183

to the left side

- 3 x^{2} + 49 x - 183 = - 5 x

Move

5 x

to the left side

- 3 x^{2} + 54 x - 183 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 54 \pm 5 4 ^{2} - 4 ( - 3 ) ( - 183 )}{2 ( - 3 )}

5 4^{2} - 4 (- 3) (- 183) = 125

x_{1, 2} = \frac{- 54 \pm 12 5}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 54 + 12 5}{2 ( - 3 )}, x_{2} = \frac{- 54 - 12 5}{2 ( - 3 )}

x = \frac{- 54 + 12 5}{2 ( - 3 )} : 9 - 25

x = \frac{- 54 - 12 5}{2 ( - 3 )} : 9 + 25

The solutions to the quadratic equation are:

x = 9 - 25, x = 9 + 25

3 x^{2} - 6 x - 10

m^{2} = 5 m + 14

x^{2} + 2 x + 10 = - 2

- 9 x^{2} + 18 x + 35 = 0

7 x^{2} + 40 x = 12

What are the solutions to the equation -3x^2+49x=-5x+183 ?
The solutions to the equation -3x^2+49x=-5x+183 are x=9-2sqrt(5),x=9+2sqrt(5)
Find the zeros of -3x^2+49x=-5x+183
The zeros of -3x^2+49x=-5x+183 are x=9-2sqrt(5),x=9+2sqrt(5)