What are the solutions to the equation 4x^2+28x=0 ?

The solutions to the equation 4x^2+28x=0 are x=0,x=-7

Find the zeros of 4x^2+28x=0

The zeros of 4x^2+28x=0 are x=0,x=-7

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4 x^{2} + 28 x = 0

x = 0, x = - 7

Solution steps

4 x^{2} + 28 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 28 \pm 2 8 ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

2 8^{2} - 4 \cdot 4 \cdot 0 = 28

x_{1, 2} = \frac{- 28 \pm 28}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 28 + 28}{2 \cdot 4}, x_{2} = \frac{- 28 - 28}{2 \cdot 4}

x = \frac{- 28 + 28}{2 \cdot 4} : 0

x = \frac{- 28 - 28}{2 \cdot 4} : - 7

The solutions to the quadratic equation are:

x = 0, x = - 7

\frac{42 y z ^{4}}{- 48 x z ^{3}}

- (\frac{5}{2})^{- 2}

5 x^{2} - x = 4

c^{2} + 3^{2} = 7^{2}

7 (\frac{2 ( 3 n - 5 ) - 8 + 1}{6}) - 4 = 73

What are the solutions to the equation 4x^2+28x=0 ?
The solutions to the equation 4x^2+28x=0 are x=0,x=-7
Find the zeros of 4x^2+28x=0
The zeros of 4x^2+28x=0 are x=0,x=-7