What are the solutions to the equation factor 2x^2+15x-11=-3 ?

The solutions to the equation factor 2x^2+15x-11=-3 are x= 1/2 ,x=-8

Find the zeros of factor 2x^2+15x-11=-3

The zeros of factor 2x^2+15x-11=-3 are x= 1/2 ,x=-8

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2 x^{2} + 15 x - 11 = - 3

x = \frac{1}{2}, x = - 8

Decimal

x = 0.5, x = - 8

Solution steps

2 x^{2} + 15 x - 11 = - 3

Move

3

to the left side

2 x^{2} + 15 x - 8 = 0

Factor

2 x^{2} + 15 x - 8 : (2 x - 1) (x + 8)

(2 x - 1) (x + 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 1 = 0 or x + 8 = 0

Solve

2 x - 1 = 0 : x = \frac{1}{2}

Solve

x + 8 = 0 : x = - 8

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - 8

21 c^{2} - 16 c - 6 = 1 - 2 c

- \frac{40}{3} = - \frac{10}{3} x^{2}

(x - 11)^{2} - 81 = 0

4800008 x^{2} = 0.0233 - x

d^{2} - 12 d - 14 = - 6 d

What are the solutions to the equation factor 2x^2+15x-11=-3 ?
The solutions to the equation factor 2x^2+15x-11=-3 are x= 1/2 ,x=-8
Find the zeros of factor 2x^2+15x-11=-3
The zeros of factor 2x^2+15x-11=-3 are x= 1/2 ,x=-8