What are the solutions to the equation 3x^2+24x+40=0 ?

The solutions to the equation 3x^2+24x+40=0 are x=(2(sqrt(6)-6))/3 ,x=-(2(6+sqrt(6)))/3

Find the zeros of 3x^2+24x+40=0

The zeros of 3x^2+24x+40=0 are x=(2(sqrt(6)-6))/3 ,x=-(2(6+sqrt(6)))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} + 24 x + 40 = 0

x = \frac{2 ( 6 - 6 )}{3}, x = - \frac{2 ( 6 + 6 )}{3}

Decimal Notation

x = - 2.36700 \dots, x = - 5.63299 \dots

Solution steps

3 x^{2} + 24 x + 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 3 \cdot 40}{2 \cdot 3}

2 4^{2} - 4 \cdot 3 \cdot 40 = 46

x_{1, 2} = \frac{- 24 \pm 4 6}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 24 + 4 6}{2 \cdot 3}, x_{2} = \frac{- 24 - 4 6}{2 \cdot 3}

x = \frac{- 24 + 4 6}{2 \cdot 3} : \frac{2 ( 6 - 6 )}{3}

x = \frac{- 24 - 4 6}{2 \cdot 3} : - \frac{2 ( 6 + 6 )}{3}

The solutions to the quadratic equation are:

x = \frac{2 ( 6 - 6 )}{3}, x = - \frac{2 ( 6 + 6 )}{3}

- 2 - 3 (x - 5)^{2} = - 29

(2 x - 1)^{2} - 16 = 9

x^{2} - x = 380

6 x^{2} - 18 x - 24 = 74

2 x^{2} - 3 x - 135 = 0

What are the solutions to the equation 3x^2+24x+40=0 ?
The solutions to the equation 3x^2+24x+40=0 are x=(2(sqrt(6)-6))/3 ,x=-(2(6+sqrt(6)))/3
Find the zeros of 3x^2+24x+40=0
The zeros of 3x^2+24x+40=0 are x=(2(sqrt(6)-6))/3 ,x=-(2(6+sqrt(6)))/3