What are the solutions to the equation -2-3(x-5)^2=-29 ?

The solutions to the equation -2-3(x-5)^2=-29 are x=8,x=2

Find the zeros of -2-3(x-5)^2=-29

The zeros of -2-3(x-5)^2=-29 are x=8,x=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 2 - 3 (x - 5)^{2} = - 29

x = 8, x = 2

Solution steps

- 2 - 3 (x - 5)^{2} = - 29

Move

2

to the right side

- 3 (x - 5)^{2} = - 27

Divide both sides by

- 3

(x - 5)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 5 = 9 : x = 8

Solve

x - 5 = - 9 : x = 2

The solutions to the quadratic equation are:

x = 8, x = 2

(2 x - 1)^{2} - 16 = 9

x^{2} - x = 380

6 x^{2} - 18 x - 24 = 74

2 x^{2} - 3 x - 135 = 0

x^{2} - 6 x + 16

What are the solutions to the equation -2-3(x-5)^2=-29 ?
The solutions to the equation -2-3(x-5)^2=-29 are x=8,x=2
Find the zeros of -2-3(x-5)^2=-29
The zeros of -2-3(x-5)^2=-29 are x=8,x=2