What are the solutions to the equation 36=12x-x^2 ?

The solutions to the equation 36=12x-x^2 are x=6

Find the zeros of 36=12x-x^2

The zeros of 36=12x-x^2 are x=6

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36 = 12 x - x^{2}

x = 6

Solution steps

36 = 12 x - x^{2}

Switch sides

12 x - x^{2} = 36

Move

36

to the left side

12 x - x^{2} - 36 = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + 12 x - 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 1 ) ( - 36 )}{2 ( - 1 )}

1 2^{2} - 4 (- 1) (- 36) = 0

x_{1, 2} = \frac{- 12 \pm 0}{2 ( - 1 )}

x = \frac{- 12}{2 ( - 1 )}

\frac{- 12}{2 ( - 1 )} = 6

x = 6

The solution to the quadratic equation is:

x = 6

x^{2} - 6 x - 16

0 = - 4.9 t^{2} - 44.1 t + 176.4

- 16 t^{2} + 34 t + 42 = 0

x^{2} - 8 (x + 3) = + 4 x - 45

2 x^{2} + 3 x - 54 = 0

What are the solutions to the equation 36=12x-x^2 ?
The solutions to the equation 36=12x-x^2 are x=6
Find the zeros of 36=12x-x^2
The zeros of 36=12x-x^2 are x=6