What are the solutions to the equation -6x^2+60x-96=0 ?

The solutions to the equation -6x^2+60x-96=0 are x=2,x=8

Find the zeros of -6x^2+60x-96=0

The zeros of -6x^2+60x-96=0 are x=2,x=8

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- 6 x^{2} + 60 x - 96 = 0

x = 2, x = 8

Solution steps

- 6 x^{2} + 60 x - 96 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 60 \pm 6 0 ^{2} - 4 ( - 6 ) ( - 96 )}{2 ( - 6 )}

6 0^{2} - 4 (- 6) (- 96) = 36

x_{1, 2} = \frac{- 60 \pm 36}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- 60 + 36}{2 ( - 6 )}, x_{2} = \frac{- 60 - 36}{2 ( - 6 )}

x = \frac{- 60 + 36}{2 ( - 6 )} : 2

x = \frac{- 60 - 36}{2 ( - 6 )} : 8

The solutions to the quadratic equation are:

x = 2, x = 8

x^{2} + 18 x + 27 = 8 x + 3

12 a^{2} - 22 a - 5 = - 5 a

9 x^{2} + 6 x + 5

x^{2} - 15 = 2 x

0 = 6 x^{2} - 8

What are the solutions to the equation -6x^2+60x-96=0 ?
The solutions to the equation -6x^2+60x-96=0 are x=2,x=8
Find the zeros of -6x^2+60x-96=0
The zeros of -6x^2+60x-96=0 are x=2,x=8