What are the solutions to the equation 3x^2-42x+80=0 ?

The solutions to the equation 3x^2-42x+80=0 are x=(21+sqrt(201))/3 ,x=(21-sqrt(201))/3

Find the zeros of 3x^2-42x+80=0

The zeros of 3x^2-42x+80=0 are x=(21+sqrt(201))/3 ,x=(21-sqrt(201))/3

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3 x^{2} - 42 x + 80 = 0

x = \frac{21 + 201}{3}, x = \frac{21 - 201}{3}

Decimal Notation

x = 11.72581 \dots, x = 2.27418 \dots

Solution steps

3 x^{2} - 42 x + 80 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 42 ) \pm ( - 42 ) ^{2} - 4 \cdot 3 \cdot 80}{2 \cdot 3}

(- 42)^{2} - 4 \cdot 3 \cdot 80 = 2201

x_{1, 2} = \frac{- ( - 42 ) \pm 2 201}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 42 ) + 2 201}{2 \cdot 3}, x_{2} = \frac{- ( - 42 ) - 2 201}{2 \cdot 3}

x = \frac{- ( - 42 ) + 2 201}{2 \cdot 3} : \frac{21 + 201}{3}

x = \frac{- ( - 42 ) - 2 201}{2 \cdot 3} : \frac{21 - 201}{3}

The solutions to the quadratic equation are:

x = \frac{21 + 201}{3}, x = \frac{21 - 201}{3}

y, x^{2} + y^{3} = 8

6 x^{2} = x + 15

2 x + 7 = - x^{2}

x^{2} - 0.6 x + 0.09 = 0

9 x^{2} + 12 = 0

What are the solutions to the equation 3x^2-42x+80=0 ?
The solutions to the equation 3x^2-42x+80=0 are x=(21+sqrt(201))/3 ,x=(21-sqrt(201))/3
Find the zeros of 3x^2-42x+80=0
The zeros of 3x^2-42x+80=0 are x=(21+sqrt(201))/3 ,x=(21-sqrt(201))/3