What are the solutions to the equation 9x^2+12=0 ?

The solutions to the equation 9x^2+12=0 are x= 2/(sqrt(3))i,x=-2/(sqrt(3))i

Find the zeros of 9x^2+12=0

The zeros of 9x^2+12=0 are x= 2/(sqrt(3))i,x=-2/(sqrt(3))i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9 x^{2} + 12 = 0

x = \frac{2}{3} i, x = - \frac{2}{3} i

Solution steps

9 x^{2} + 12 = 0

Move

12

to the right side

9 x^{2} = - 12

Divide both sides by

9

x^{2} = - \frac{4}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{4}{3}, x = - - \frac{4}{3}

- \frac{4}{3} = \frac{2}{3} i

- - \frac{4}{3} = - \frac{2}{3} i

x = \frac{2}{3} i, x = - \frac{2}{3} i

4 x^{2} + 44 x + 96 = 0

- 0.3 x^{2} - 3.5 x + 20 = 0

- y^{2} - 2 y

3 a^{2} + 8 a + 5 = 0

6750000 = 100 x - 0.0001 x^{2}

What are the solutions to the equation 9x^2+12=0 ?
The solutions to the equation 9x^2+12=0 are x= 2/(sqrt(3))i,x=-2/(sqrt(3))i
Find the zeros of 9x^2+12=0
The zeros of 9x^2+12=0 are x= 2/(sqrt(3))i,x=-2/(sqrt(3))i