What are the solutions to the equation m^2= 24/3 ,m^1=8 ?

The solutions to the equation m^2= 24/3 ,m^1=8 are m=2sqrt(2),m=-2sqrt(2)

Find the zeros of m^2= 24/3 ,m^1=8

The zeros of m^2= 24/3 ,m^1=8 are m=2sqrt(2),m=-2sqrt(2)

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m^{2} = \frac{24}{3}, m^{1} = 8

m = 22, m = - 22

Decimal Notation

m = 2.82842 \dots, m = - 2.82842 \dots

Solution steps

m^{2} = \frac{24}{3}, m^{1} = 8

Divide the numbers:

\frac{24}{3} = 8

m^{2} = 8

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

m = 8, m = - 8

8 = 22

- 8 = - 22

m = 22, m = - 22

3 n^{2} - n - 4 = 0

x^{2} + 7 - 8 x = 0

2 (x - 1)^{2} = 10 x

3 x^{2} + 90 = 36 x

a x^{2} + e x + n = 0

What are the solutions to the equation m^2= 24/3 ,m^1=8 ?
The solutions to the equation m^2= 24/3 ,m^1=8 are m=2sqrt(2),m=-2sqrt(2)
Find the zeros of m^2= 24/3 ,m^1=8
The zeros of m^2= 24/3 ,m^1=8 are m=2sqrt(2),m=-2sqrt(2)