What are the solutions to the equation 3n^2-n-4=0 ?

The solutions to the equation 3n^2-n-4=0 are n= 4/3 ,n=-1

Find the zeros of 3n^2-n-4=0

The zeros of 3n^2-n-4=0 are n= 4/3 ,n=-1

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3 n^{2} - n - 4 = 0

n = \frac{4}{3}, n = - 1

Decimal Notation

n = 1.33333 \dots, n = - 1

Solution steps

3 n^{2} - n - 4 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 3 ( - 4 )}{2 \cdot 3}

(- 1)^{2} - 4 \cdot 3 (- 4) = 7

n_{1, 2} = \frac{- ( - 1 ) \pm 7}{2 \cdot 3}

Separate the solutions

n_{1} = \frac{- ( - 1 ) + 7}{2 \cdot 3}, n_{2} = \frac{- ( - 1 ) - 7}{2 \cdot 3}

n = \frac{- ( - 1 ) + 7}{2 \cdot 3} : \frac{4}{3}

n = \frac{- ( - 1 ) - 7}{2 \cdot 3} : - 1

The solutions to the quadratic equation are:

n = \frac{4}{3}, n = - 1

x^{2} + 7 - 8 x = 0

2 (x - 1)^{2} = 10 x

3 x^{2} + 90 = 36 x

a x^{2} + e x + n = 0

25 - (x + 3)^{2} = 0

What are the solutions to the equation 3n^2-n-4=0 ?
The solutions to the equation 3n^2-n-4=0 are n= 4/3 ,n=-1
Find the zeros of 3n^2-n-4=0
The zeros of 3n^2-n-4=0 are n= 4/3 ,n=-1