What are the solutions to the equation 25-(x+3)^2=0 ?

The solutions to the equation 25-(x+3)^2=0 are x=2,x=-8

Find the zeros of 25-(x+3)^2=0

The zeros of 25-(x+3)^2=0 are x=2,x=-8

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25 - (x + 3)^{2} = 0

x = 2, x = - 8

Solution steps

25 - (x + 3)^{2} = 0

Move

25

to the right side

- (x + 3)^{2} = - 25

Divide both sides by

- 1

(x + 3)^{2} = 25

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = 25 : x = 2

Solve

x + 3 = - 25 : x = - 8

The solutions to the quadratic equation are:

x = 2, x = - 8

4 x^{2} + 4 x - 17 = 0

w^{2} + 8 w - 6 = 0

r^{2} + 16

0.513 x \frac{0.05}{4} = x^{2}

r^{2} + 2 r + 64 = 0

What are the solutions to the equation 25-(x+3)^2=0 ?
The solutions to the equation 25-(x+3)^2=0 are x=2,x=-8
Find the zeros of 25-(x+3)^2=0
The zeros of 25-(x+3)^2=0 are x=2,x=-8