What are the solutions to the equation 0=-16x^2+8x+8 ?

The solutions to the equation 0=-16x^2+8x+8 are x=-1/2 ,x=1

Find the zeros of 0=-16x^2+8x+8

The zeros of 0=-16x^2+8x+8 are x=-1/2 ,x=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = - 16 x^{2} + 8 x + 8

x = - \frac{1}{2}, x = 1

Decimal Notation

x = - 0.5, x = 1

Solution steps

0 = - 16 x^{2} + 8 x + 8

Switch sides

- 16 x^{2} + 8 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 16 ) \cdot 8}{2 ( - 16 )}

8^{2} - 4 (- 16) \cdot 8 = 24

x_{1, 2} = \frac{- 8 \pm 24}{2 ( - 16 )}

Separate the solutions

x_{1} = \frac{- 8 + 24}{2 ( - 16 )}, x_{2} = \frac{- 8 - 24}{2 ( - 16 )}

x = \frac{- 8 + 24}{2 ( - 16 )} : - \frac{1}{2}

x = \frac{- 8 - 24}{2 ( - 16 )} : 1

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = 1

0 = - x^{2} + 4 x - 1

(x + 4) (x - 4) - (x - 2)^{2} = x (x - 5)

x = - x^{2} + 1000 x

- x^{2} + 3 x + a = 0

0 = 12 x^{2} - 24 x - 40

What are the solutions to the equation 0=-16x^2+8x+8 ?
The solutions to the equation 0=-16x^2+8x+8 are x=-1/2 ,x=1
Find the zeros of 0=-16x^2+8x+8
The zeros of 0=-16x^2+8x+8 are x=-1/2 ,x=1