What are the solutions to the equation -16x^2=20x^2+24x+5 ?

The solutions to the equation -16x^2=20x^2+24x+5 are x=-1/3+i 1/6 ,x=-1/3-i 1/6

Find the zeros of -16x^2=20x^2+24x+5

The zeros of -16x^2=20x^2+24x+5 are x=-1/3+i 1/6 ,x=-1/3-i 1/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 16 x^{2} = 20 x^{2} + 24 x + 5

x = - \frac{1}{3} + i \frac{1}{6}, x = - \frac{1}{3} - i \frac{1}{6}

Solution steps

- 16 x^{2} = 20 x^{2} + 24 x + 5

Switch sides

20 x^{2} + 24 x + 5 = - 16 x^{2}

Move

16 x^{2}

to the left side

36 x^{2} + 24 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 36 \cdot 5}{2 \cdot 36}

Simplify

2 4^{2} - 4 \cdot 36 \cdot 5 : 12 i

x_{1, 2} = \frac{- 24 \pm 12 i}{2 \cdot 36}

Separate the solutions

x_{1} = \frac{- 24 + 12 i}{2 \cdot 36}, x_{2} = \frac{- 24 - 12 i}{2 \cdot 36}

x = \frac{- 24 + 12 i}{2 \cdot 36} : - \frac{1}{3} + i \frac{1}{6}

x = \frac{- 24 - 12 i}{2 \cdot 36} : - \frac{1}{3} - i \frac{1}{6}

The solutions to the quadratic equation are:

x = - \frac{1}{3} + i \frac{1}{6}, x = - \frac{1}{3} - i \frac{1}{6}

10 x^{2} - 27 x + 18 = 0

(- 2 x + 7) (x - 1) = 3

n^{2} + 3 n = 10

s, (s + 4)^{2} + 9 = 0

3 x^{2} + 4 x + 9 = 8

What are the solutions to the equation -16x^2=20x^2+24x+5 ?
The solutions to the equation -16x^2=20x^2+24x+5 are x=-1/3+i 1/6 ,x=-1/3-i 1/6
Find the zeros of -16x^2=20x^2+24x+5
The zeros of -16x^2=20x^2+24x+5 are x=-1/3+i 1/6 ,x=-1/3-i 1/6