What are the solutions to the equation -20x^2=4x ?

The solutions to the equation -20x^2=4x are x=0,x=-1/5

Find the zeros of -20x^2=4x

The zeros of -20x^2=4x are x=0,x=-1/5

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- 20 x^{2} = 4 x

x = 0, x = - \frac{1}{5}

Decimal Notation

x = 0, x = - 0.2

Solution steps

- 20 x^{2} = 4 x

Move

4 x

to the left side

- 20 x^{2} - 4 x = 0

Factor

- 20 x^{2} - 4 x : - 4 x (5 x + 1)

- 4 x (5 x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 5 x + 1 = 0

Solve

5 x + 1 = 0 : x = - \frac{1}{5}

The solutions to the quadratic equation are:

x = 0, x = - \frac{1}{5}

- 3 x^{2} - 7 x + 5

60 x^{2} - 180 x = 0

f, f^{- 1} (x) = x^{2} - 2

f, f^{- 1} (x) = x^{2} - 4

d^{2} = 4 (3 d + 7)

What are the solutions to the equation -20x^2=4x ?
The solutions to the equation -20x^2=4x are x=0,x=-1/5
Find the zeros of -20x^2=4x
The zeros of -20x^2=4x are x=0,x=-1/5