What are the solutions to the equation 60x^2-180x=0 ?

The solutions to the equation 60x^2-180x=0 are x=3,x=0

Find the zeros of 60x^2-180x=0

The zeros of 60x^2-180x=0 are x=3,x=0

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60 x^{2} - 180 x = 0

x = 3, x = 0

Solution steps

60 x^{2} - 180 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 180 ) \pm ( - 180 ) ^{2} - 4 \cdot 60 \cdot 0}{2 \cdot 60}

(- 180)^{2} - 4 \cdot 60 \cdot 0 = 180

x_{1, 2} = \frac{- ( - 180 ) \pm 180}{2 \cdot 60}

Separate the solutions

x_{1} = \frac{- ( - 180 ) + 180}{2 \cdot 60}, x_{2} = \frac{- ( - 180 ) - 180}{2 \cdot 60}

x = \frac{- ( - 180 ) + 180}{2 \cdot 60} : 3

x = \frac{- ( - 180 ) - 180}{2 \cdot 60} : 0

The solutions to the quadratic equation are:

x = 3, x = 0

f, f^{- 1} (x) = x^{2} - 2

f, f^{- 1} (x) = x^{2} - 4

d^{2} = 4 (3 d + 7)

- 2 x^{2} - 12 x - 8 = 0

(3 x - 7)^{2} + 4 = 29

What are the solutions to the equation 60x^2-180x=0 ?
The solutions to the equation 60x^2-180x=0 are x=3,x=0
Find the zeros of 60x^2-180x=0
The zeros of 60x^2-180x=0 are x=3,x=0