What are the solutions to the equation -5x^2+35x-50=-200 ?

The solutions to the equation -5x^2+35x-50=-200 are x=-3,x=10

Find the zeros of -5x^2+35x-50=-200

The zeros of -5x^2+35x-50=-200 are x=-3,x=10

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- 5 x^{2} + 35 x - 50 = - 200

x = - 3, x = 10

Solution steps

- 5 x^{2} + 35 x - 50 = - 200

Move

200

to the left side

- 5 x^{2} + 35 x + 150 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 35 \pm 3 5 ^{2} - 4 ( - 5 ) \cdot 150}{2 ( - 5 )}

3 5^{2} - 4 (- 5) \cdot 150 = 65

x_{1, 2} = \frac{- 35 \pm 65}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 35 + 65}{2 ( - 5 )}, x_{2} = \frac{- 35 - 65}{2 ( - 5 )}

x = \frac{- 35 + 65}{2 ( - 5 )} : - 3

x = \frac{- 35 - 65}{2 ( - 5 )} : 10

The solutions to the quadratic equation are:

x = - 3, x = 10

4 x^{2} = (x + 1)^{2} + b

y, (x - 1)^{2} + y^{2} = 0

x^{2} + 16 x + 71

x^{2} - 109 = - 8 x

x^{2} = 1 2^{2} + 6^{2}

What are the solutions to the equation -5x^2+35x-50=-200 ?
The solutions to the equation -5x^2+35x-50=-200 are x=-3,x=10
Find the zeros of -5x^2+35x-50=-200
The zeros of -5x^2+35x-50=-200 are x=-3,x=10