What is the answer to 1/(x-1)-2/(x^2)=0 ?

The answer to 1/(x-1)-2/(x^2)=0 is x=1+i,x=1-i

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1/(x-1)-2/(x^2)=0

\frac{1}{x - 1} - \frac{2}{x ^{2}} = 0

x = 1 + i, x = 1 - i

Solution steps

\frac{1}{x - 1} - \frac{2}{x ^{2}} = 0

Multiply by LCM

x^{2} - 2 (x - 1) = 0

Solve

x^{2} - 2 (x - 1) = 0 : x = 1 + i, x = 1 - i

x = 1 + i, x = 1 - i

\frac{9 x}{2 x ^{2}} = 2

\frac{7}{x - 5} = 2

\frac{3 x + 7}{x - 1} = - 1

\frac{4}{x - 4} = - 5

\frac{2 x}{2 x + 3} - \frac{2 x}{2 x - 3} = 1

What is the answer to 1/(x-1)-2/(x^2)=0 ?
The answer to 1/(x-1)-2/(x^2)=0 is x=1+i,x=1-i
Solve for x: 1/(x-1)-2/(x^2)=0
The solution is x=1+i,x=1-i