What is the answer to x/(x^2-4)+1/(x+2)=3 ?

The answer to x/(x^2-4)+1/(x+2)=3 is x=(1+sqrt(31))/3 ,x=(1-sqrt(31))/3

Solve for x: x/(x^2-4)+1/(x+2)=3

The solution is x=(1+sqrt(31))/3 ,x=(1-sqrt(31))/3

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\frac{x}{x ^{2} - 4} + \frac{1}{x + 2} = 3

x = \frac{1 + 31}{3}, x = \frac{1 - 31}{3}

Decimal Notation

x = 2.18925 \dots, x = - 1.52258 \dots

Solution steps

\frac{x}{x ^{2} - 4} + \frac{1}{x + 2} = 3

Multiply by LCM

2 x - 2 = 3 (x + 2) (x - 2)

Solve

2 x - 2 = 3 (x + 2) (x - 2) : x = \frac{1 + 31}{3}, x = \frac{1 - 31}{3}

x = \frac{1 + 31}{3}, x = \frac{1 - 31}{3}

Verify Solutions

Find undefined (singularity) points:

x = 2, x = - 2

Combine undefined points with solutions:

x = \frac{1 + 31}{3}, x = \frac{1 - 31}{3}

\frac{x ^{2} - 1}{x - 3} = \frac{8}{x - 3}

k, t = p + \frac{x n}{k}

x + 1 = \frac{4}{x + 1}

\frac{3}{x} - \frac{1}{2} = \frac{12}{x}

\frac{3}{x} - \frac{1}{3} = \frac{1}{6}

What is the answer to x/(x^2-4)+1/(x+2)=3 ?
The answer to x/(x^2-4)+1/(x+2)=3 is x=(1+sqrt(31))/3 ,x=(1-sqrt(31))/3
Solve for x: x/(x^2-4)+1/(x+2)=3
The solution is x=(1+sqrt(31))/3 ,x=(1-sqrt(31))/3