What is the answer to (x^2-1)/(x-3)= 8/(x-3) ?

The answer to (x^2-1)/(x-3)= 8/(x-3) is x=-3

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(x^2-1)/(x-3)= 8/(x-3)

\frac{x ^{2} - 1}{x - 3} = \frac{8}{x - 3}

x = - 3

Solution steps

\frac{x ^{2} - 1}{x - 3} = \frac{8}{x - 3}

Multiply both sides by

x - 3

x^{2} - 1 = 8

Solve

x^{2} - 1 = 8 : x = 3, x = - 3

x = 3, x = - 3

Verify Solutions

Find undefined (singularity) points:

x = 3

Since the equation is undefined for:

3

x = - 3

k, t = p + \frac{x n}{k}

x + 1 = \frac{4}{x + 1}

\frac{3}{x} - \frac{1}{2} = \frac{12}{x}

\frac{3}{x} - \frac{1}{3} = \frac{1}{6}

\frac{2}{x ^{2} - x} = \frac{1}{x - 1}

What is the answer to (x^2-1)/(x-3)= 8/(x-3) ?
The answer to (x^2-1)/(x-3)= 8/(x-3) is x=-3
Solve for x: (x^2-1)/(x-3)= 8/(x-3)
The solution is x=-3