What is the answer to x^2+36x^{-2}-13=0 ?

The answer to x^2+36x^{-2}-13=0 is x=3,x=-3,x=2,x=-2

Solve for x: x^2+36x^{-2}-13=0

The solution is x=3,x=-3,x=2,x=-2

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x^{2} + 36 x^{- 2} - 13 = 0

x = 3, x = - 3, x = 2, x = - 2

Solution steps

x^{2} + 36 x^{- 2} - 13 = 0

Refine

x^{2} + \frac{36}{x ^{2}} - 13 = 0

Multiply both sides by

x^{2}

x^{4} + 36 - 13 x^{2} = 0

Solve

x^{4} + 36 - 13 x^{2} = 0 : x = 3, x = - 3, x = 2, x = - 2

x = 3, x = - 3, x = 2, x = - 2

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = 3, x = - 3, x = 2, x = - 2

\frac{y ^{2}}{y - 3} = \frac{18}{2 y - 6}

\frac{3}{x} + \frac{x}{10} = \frac{11}{2 x}

- \frac{7}{2 u + 12} + 1 = - \frac{3}{u + 6}

\frac{250}{x} + \frac{360}{x + 10} = 11

\frac{6}{x - 6} - \frac{12}{x ^{2}} = 0

What is the answer to x^2+36x^{-2}-13=0 ?
The answer to x^2+36x^{-2}-13=0 is x=3,x=-3,x=2,x=-2
Solve for x: x^2+36x^{-2}-13=0
The solution is x=3,x=-3,x=2,x=-2