What is the answer to (y^2)/(y-3)=(18)/(2y-6) ?

The answer to (y^2)/(y-3)=(18)/(2y-6) is y=-3

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(y^2)/(y-3)=(18)/(2y-6)

\frac{y ^{2}}{y - 3} = \frac{18}{2 y - 6}

y = - 3

Solution steps

\frac{y ^{2}}{y - 3} = \frac{18}{2 y - 6}

Simplify

\frac{18}{2 y - 6} : \frac{9}{y - 3}

\frac{y ^{2}}{y - 3} = \frac{9}{y - 3}

Multiply both sides by

y - 3

y^{2} = 9

Solve

y^{2} = 9 : y = 3, y = - 3

y = 3, y = - 3

Verify Solutions

Find undefined (singularity) points:

y = 3

Since the equation is undefined for:

3

y = - 3

\frac{3}{x} + \frac{x}{10} = \frac{11}{2 x}

- \frac{7}{2 u + 12} + 1 = - \frac{3}{u + 6}

\frac{250}{x} + \frac{360}{x + 10} = 11

\frac{6}{x - 6} - \frac{12}{x ^{2}} = 0

2 x^{- 2} = x^{- 1} - 1

What is the answer to (y^2)/(y-3)=(18)/(2y-6) ?
The answer to (y^2)/(y-3)=(18)/(2y-6) is y=-3
Solve for y: (y^2)/(y-3)=(18)/(2y-6)
The solution is y=-3