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Popular >

3+|2x+1|<= 7

Solution

3 + ∣ 2 x + 1 ∣ \leq 7

Solution

- \frac{5}{2} \leq x \leq \frac{3}{2}

+2

Interval Notation

[- \frac{5}{2}, \frac{3}{2}]

Decimal Notation

- 2.5 \leq x \leq 1.5

Solution steps

3 + ∣ 2 x + 1 ∣ \leq 7

Move

3

to the right side

∣ 2 x + 1 ∣ \leq 4

Apply absolute rule: If

∣ u ∣ \leq a, a > 0

then

- a \leq u \leq a

- 4 \leq 2 x + 1 \leq 4

2 x + 1 \geq - 4 and 2 x + 1 \leq 4

x \geq - \frac{5}{2} and x \leq \frac{3}{2}

Merge Overlapping Intervals

- \frac{5}{2} \leq x \leq \frac{3}{2}

Popular Examples

- 2 \leq - 2 x \leq 3 x - 1

simplify 2/3+1/9 simplify

\frac{2}{3} + \frac{1}{9}

simplify-2-(-4)simplify

- 2 - (- 4)

factor (x^2-x-12)/(x^2-4x-21)factor

\frac{x ^{2} - x - 12}{x ^{2} - 4 x - 21}

simplify (8^{15})/(8^3)simplify

\frac{8 ^{15}}{8 ^{3}}

Frequently Asked Questions (FAQ)

What is 3+|2x+1|<= 7 ?
The solution to 3+|2x+1|<= 7 is -5/2 <= x<= 3/2