What is factor (x^2-x-12)/(x^2-4x-21) ?

The solution to factor (x^2-x-12)/(x^2-4x-21) is (x-4)/(x-7)

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factor (x^2-x-12)/(x^2-4x-21)

factor

\frac{x ^{2} - x - 12}{x ^{2} - 4 x - 21}

\frac{x - 4}{x - 7}

Solution steps

\frac{x ^{2} - x - 12}{x ^{2} - 4 x - 21}

Factor

x^{2} - x - 12 : (x + 3) (x - 4)

= \frac{( x + 3 ) ( x - 4 )}{x ^{2} - 4 x - 21}

Factor

x^{2} - 4 x - 21 : (x + 3) (x - 7)

= \frac{( x + 3 ) ( x - 4 )}{( x + 3 ) ( x - 7 )}

Cancel the common factor:

x + 3

= \frac{x - 4}{x - 7}

\frac{8 ^{15}}{8 ^{3}}

(4 x^{5} y)^{2}

t^{2} - t - 12

5 + x^{2} = (x + 1) (x + 6)

m^{4} + m^{2} - 2

What is factor (x^2-x-12)/(x^2-4x-21) ?
The solution to factor (x^2-x-12)/(x^2-4x-21) is (x-4)/(x-7)