What are the solutions to the equation 4u^2+28=0 ?

The solutions to the equation 4u^2+28=0 are u=sqrt(7)i,u=-sqrt(7)i

Find the zeros of 4u^2+28=0

The zeros of 4u^2+28=0 are u=sqrt(7)i,u=-sqrt(7)i

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4 u^{2} + 28 = 0

u = 7 i, u = - 7 i

Solution steps

4 u^{2} + 28 = 0

Move

28

to the right side

4 u^{2} = - 28

Divide both sides by

4

u^{2} = - 7

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

u = - 7, u = - - 7

- 7 = 7 i

- - 7 = - 7 i

u = 7 i, u = - 7 i

9 x^{2} + 9 x - 4 = 0

120 = 16 t^{2}

\frac{2 ^{- 1}}{- 1}

2^{8} - 1

- a + 2 = 1

What are the solutions to the equation 4u^2+28=0 ?
The solutions to the equation 4u^2+28=0 are u=sqrt(7)i,u=-sqrt(7)i
Find the zeros of 4u^2+28=0
The zeros of 4u^2+28=0 are u=sqrt(7)i,u=-sqrt(7)i