What is the answer to roots (-2x^2+ax-35)/(3x+15) ?

The answer to roots (-2x^2+ax-35)/(3x+15) is x=-(-a+sqrt(a^2-280))/4 ,x=-(-a-sqrt(a^2-280))/4

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roots (-2x^2+ax-35)/(3x+15)

roots

\frac{- 2 x ^{2} + a x - 35}{3 x + 15}

x = - \frac{- a + a ^{2} - 280}{4}, x = - \frac{- a - a ^{2} - 280}{4}

Solution steps

\frac{- 2 x ^{2} + a x - 35}{3 x + 15}

The roots are the intercepts with the x-axis

(y = 0)

\frac{- 2 x ^{2} + a x - 35}{3 x + 15} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

- 2 x^{2} + a x - 35 = 0

Solve

- 2 x^{2} + a x - 35 = 0 : x = - \frac{- a + a ^{2} - 280}{4}, x = - \frac{- a - a ^{2} - 280}{4}

x = - \frac{- a + a ^{2} - 280}{4}, x = - \frac{- a - a ^{2} - 280}{4}

x + \frac{4}{x} = 12

\frac{6}{x + 1} = \frac{x}{x - 1}

\frac{5 x + 4}{x + 2} = \frac{8 + 4 x}{x - 3}

\frac{x ^{2}}{16} = 1 + \frac{\frac{3}{4 x}}{9}

y, - \frac{y}{x} = - 1

What is the answer to roots (-2x^2+ax-35)/(3x+15) ?
The answer to roots (-2x^2+ax-35)/(3x+15) is x=-(-a+sqrt(a^2-280))/4 ,x=-(-a-sqrt(a^2-280))/4