What is the answer to solvefor f,-f= x/(x^2+1) ?

The answer to solvefor f,-f= x/(x^2+1) is f=-x/(x^2+1)

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solvefor f,-f= x/(x^2+1)

solve for

f, - f = \frac{x}{x ^{2} + 1}

f = - \frac{x}{x ^{2} + 1}

Solution steps

- f = \frac{x}{x ^{2} + 1}

Divide both sides by

- 1

f = - \frac{x}{x ^{2} + 1}

1 - \frac{2}{x + 1} = \frac{2 x}{x ^{2} + 3 x + 2}

2 x + \frac{3}{x + 2} = 1

\frac{1}{x} = \frac{1}{5} + \frac{3}{2 x}

x, (f - g) (x) = \frac{( x ^{2} + 2 x - 1 )}{x}

6 - \frac{35}{x} + \frac{36}{x ^{2}} = 0

What is the answer to solvefor f,-f= x/(x^2+1) ?
The answer to solvefor f,-f= x/(x^2+1) is f=-x/(x^2+1)