What is the answer to (x^2+4x}{x+2}=\frac{2x)/3 ?

The answer to (x^2+4x}{x+2}=\frac{2x)/3 is x=0,x=-8

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(x^2+4x}{x+2}=\frac{2x)/3

\frac{x ^{2} + 4 x}{x + 2} = \frac{2 x}{3}

x = 0, x = - 8

Solution steps

\frac{x ^{2} + 4 x}{x + 2} = \frac{2 x}{3}

Cross multiply

(x^{2} + 4 x) \cdot 3 = (x + 2) \cdot 2 x

Solve

(x^{2} + 4 x) \cdot 3 = (x + 2) \cdot 2 x : x = 0, x = - 8

x = 0, x = - 8

Verify Solutions

Find undefined (singularity) points:

x = - 2

Combine undefined points with solutions:

x = 0, x = - 8

135 = \frac{180 ( x - 2 )}{x}

\frac{3 x ^{2} + a x + a + 3}{x ^{2} + x - 2}

1 + \frac{2}{x - 8} = \frac{2 x}{x ^{2} - x - 56}

\frac{1}{5500} = \frac{0.1}{x}

\frac{x ^{2} - 6 x + 5}{x - 1} = 0

What is the answer to (x^2+4x}{x+2}=\frac{2x)/3 ?
The answer to (x^2+4x}{x+2}=\frac{2x)/3 is x=0,x=-8
Solve for x: (x^2+4x}{x+2}=\frac{2x)/3
The solution is x=0,x=-8