What is the answer to 1+2/(x-8)=(2x)/(x^2-x-56) ?

The answer to 1+2/(x-8)=(2x)/(x^2-x-56) is x=7,x=-6

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1+2/(x-8)=(2x)/(x^2-x-56)

1 + \frac{2}{x - 8} = \frac{2 x}{x ^{2} - x - 56}

x = 7, x = - 6

Solution steps

1 + \frac{2}{x - 8} = \frac{2 x}{x ^{2} - x - 56}

Multiply by LCM

(x - 8) (x + 7) + 2 (x + 7) = 2 x

Solve

(x - 8) (x + 7) + 2 (x + 7) = 2 x : x = 7, x = - 6

x = 7, x = - 6

Verify Solutions

Find undefined (singularity) points:

x = 8, x = - 7

Combine undefined points with solutions:

x = 7, x = - 6

\frac{1}{5500} = \frac{0.1}{x}

\frac{x ^{2} - 6 x + 5}{x - 1} = 0

\frac{x + 1}{x - 2} = \frac{x + 3}{x - 4}

\frac{x}{x - 3} - \frac{x + 5}{x ^{2} - 9} = 1

\frac{1}{x} + \frac{1}{x - 2} = \frac{1}{4}

What is the answer to 1+2/(x-8)=(2x)/(x^2-x-56) ?
The answer to 1+2/(x-8)=(2x)/(x^2-x-56) is x=7,x=-6
Solve for x: 1+2/(x-8)=(2x)/(x^2-x-56)
The solution is x=7,x=-6