What is the answer to 1+1/(x+4)=(x+5)/(x^2-x-20) ?

The answer to 1+1/(x+4)=(x+5)/(x^2-x-20) is x=6,x=-5

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1+1/(x+4)=(x+5)/(x^2-x-20)

1 + \frac{1}{x + 4} = \frac{x + 5}{x ^{2} - x - 20}

x = 6, x = - 5

Solution steps

1 + \frac{1}{x + 4} = \frac{x + 5}{x ^{2} - x - 20}

Multiply by LCM

(x + 4) (x - 5) + x - 5 = x + 5

Solve

(x + 4) (x - 5) + x - 5 = x + 5 : x = 6, x = - 5

x = 6, x = - 5

Verify Solutions

Find undefined (singularity) points:

x = - 4, x = 5

Combine undefined points with solutions:

x = 6, x = - 5

1 + \frac{1}{x - 4} = \frac{4}{x ^{2} - 4 x}

x - \frac{2 x + 7}{x - 3} = \frac{x}{x - 3}

\frac{5}{a} + \frac{3}{4} = \frac{1}{a}

0 = 1 - \frac{1}{x - 3}

\frac{6 - 5 + 14}{n \times 2} = 15

What is the answer to 1+1/(x+4)=(x+5)/(x^2-x-20) ?
The answer to 1+1/(x+4)=(x+5)/(x^2-x-20) is x=6,x=-5
Solve for x: 1+1/(x+4)=(x+5)/(x^2-x-20)
The solution is x=6,x=-5