What is the answer to (y+6)/(3-y)=(5+2y)/(7y-5) ?

The answer to (y+6)/(3-y)=(5+2y)/(7y-5) is y=1,y=-5

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(y+6)/(3-y)=(5+2y)/(7y-5)

\frac{y + 6}{3 - y} = \frac{5 + 2 y}{7 y - 5}

y = 1, y = - 5

Solution steps

\frac{y + 6}{3 - y} = \frac{5 + 2 y}{7 y - 5}

Cross multiply

(y + 6) (7 y - 5) = (3 - y) (5 + 2 y)

Solve

(y + 6) (7 y - 5) = (3 - y) (5 + 2 y) : y = 1, y = - 5

y = 1, y = - 5

Verify Solutions

Find undefined (singularity) points:

y = 3, y = \frac{5}{7}

Combine undefined points with solutions:

y = 1, y = - 5

\frac{1}{x} + \frac{6}{x ^{2}} = 1

\frac{x}{x - 1} - \frac{6}{1 - x} = 2

\frac{1}{3 x - 4} = 5

\frac{x ^{10} - m ^{10}}{x ^{2} + m ^{2}}

\frac{x ^{2} + 1}{x} = \frac{4}{3}

What is the answer to (y+6)/(3-y)=(5+2y)/(7y-5) ?
The answer to (y+6)/(3-y)=(5+2y)/(7y-5) is y=1,y=-5
Solve for y: (y+6)/(3-y)=(5+2y)/(7y-5)
The solution is y=1,y=-5