What is the answer to x^{-1}+x=3x^{-1} ?

The answer to x^{-1}+x=3x^{-1} is x=sqrt(2),x=-sqrt(2)

Solve for x: x^{-1}+x=3x^{-1}

The solution is x=sqrt(2),x=-sqrt(2)

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x^{- 1} + x = 3 x^{- 1}

x = 2, x = - 2

Decimal Notation

x = 1.41421 \dots, x = - 1.41421 \dots

Solution steps

x^{- 1} + x = 3 x^{- 1}

Refine

\frac{1}{x} + x = \frac{3}{x}

Multiply both sides by

x

1 + x^{2} = 3

Solve

1 + x^{2} = 3 : x = 2, x = - 2

x = 2, x = - 2

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = 2, x = - 2

\frac{4}{2 y - 3} = \frac{7}{3 y - 5}

34 - \frac{1}{x ^{2}} = 0

\frac{1}{3 x + 3} = \frac{1}{6} - \frac{2}{x + 1}

\frac{x - 9}{3 x - 1} = \frac{x - 9}{x + 33}

- 6 = \frac{e ^{\frac{- 1 + C}{- 1}}}{x}

What is the answer to x^{-1}+x=3x^{-1} ?
The answer to x^{-1}+x=3x^{-1} is x=sqrt(2),x=-sqrt(2)
Solve for x: x^{-1}+x=3x^{-1}
The solution is x=sqrt(2),x=-sqrt(2)