What is the answer to solvefor y,(3y-x)/(3-2x)=-4 ?

The answer to solvefor y,(3y-x)/(3-2x)=-4 is y=-4+3x;\quad x\ne 3/2

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solvefor y,(3y-x)/(3-2x)=-4

solve for

y, \frac{3 y - x}{3 - 2 x} = - 4

y = - 4 + 3 x; x \neq = \frac{3}{2}

Solution steps

\frac{3 y - x}{3 - 2 x} = - 4

Multiply both sides by

3 - 2 x

3 y - x = - 4 (3 - 2 x); x \neq = \frac{3}{2}

Move

x

to the right side

3 y = - 12 + 9 x; x \neq = \frac{3}{2}

Divide both sides by

3; x \neq = \frac{3}{2}

y = - 4 + 3 x; x \neq = \frac{3}{2}

\frac{2}{x + 1} - \frac{1}{3} = \frac{1}{4 x + 4}

\frac{2 x + 7}{5 - x} = \frac{8}{3}

\frac{s ^{6} - n ^{9}}{s ^{6} - n ^{6}}

0 = \frac{2}{x ^{3}}

y, x = \frac{x + y}{x - y}

What is the answer to solvefor y,(3y-x)/(3-2x)=-4 ?
The answer to solvefor y,(3y-x)/(3-2x)=-4 is y=-4+3x;\quad x\ne 3/2