What is the answer to (3x^2-2)/(x^2+x+1)= 2/1 ?

The answer to (3x^2-2)/(x^2+x+1)= 2/1 is x=1-sqrt(5),x=1+sqrt(5)

Solve for x: (3x^2-2)/(x^2+x+1)= 2/1

The solution is x=1-sqrt(5),x=1+sqrt(5)

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\frac{3 x ^{2} - 2}{x ^{2} + x + 1} = \frac{2}{1}

x = 1 - 5, x = 1 + 5

Decimal Notation

x = - 1.23606 \dots, x = 3.23606 \dots

Solution steps

\frac{3 x ^{2} - 2}{x ^{2} + x + 1} = \frac{2}{1}

Cross multiply

3 x^{2} - 2 = (x^{2} + x + 1) \cdot 2

Solve

3 x^{2} - 2 = (x^{2} + x + 1) \cdot 2 : x = 1 - 5, x = 1 + 5

x = 1 - 5, x = 1 + 5

\frac{1}{x ^{2}} + \frac{8}{x} + 15 = 0

80 x - \frac{360}{x ^{2}} = 0

\frac{19}{4 a} - \frac{2}{a} = 1

\frac{2}{x - 2} - \frac{4}{x ^{2} - 2 x} = 3

\frac{2}{x + 1} + \frac{3}{x} = \frac{5}{x - 2}

What is the answer to (3x^2-2)/(x^2+x+1)= 2/1 ?
The answer to (3x^2-2)/(x^2+x+1)= 2/1 is x=1-sqrt(5),x=1+sqrt(5)
Solve for x: (3x^2-2)/(x^2+x+1)= 2/1
The solution is x=1-sqrt(5),x=1+sqrt(5)