What is the answer to (4x)/(x^2-9)= 8/(x-3) ?

The answer to (4x)/(x^2-9)= 8/(x-3) is x=-6

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(4x)/(x^2-9)= 8/(x-3)

\frac{4 x}{x ^{2} - 9} = \frac{8}{x - 3}

x = - 6

Solution steps

\frac{4 x}{x ^{2} - 9} = \frac{8}{x - 3}

Cross multiply

4 x (x - 3) = (x^{2} - 9) \cdot 8

Solve

4 x (x - 3) = (x^{2} - 9) \cdot 8 : x = 3, x = - 6

x = 3, x = - 6

Verify Solutions

Find undefined (singularity) points:

x = - 3, x = 3

Since the equation is undefined for:

3

x = - 6

x - \frac{2}{x} = 4

4 - \frac{1}{t} - \frac{3}{t ^{2}} = 0

\frac{x ^{2} - 6 x}{3 x - 1} = \frac{3 x - 4}{1 - 3 x}

x - \frac{5}{x + 6} = 2 x

\frac{2 x - 5}{x - 4} = \frac{11}{x - 4}

What is the answer to (4x)/(x^2-9)= 8/(x-3) ?
The answer to (4x)/(x^2-9)= 8/(x-3) is x=-6
Solve for x: (4x)/(x^2-9)= 8/(x-3)
The solution is x=-6