What is the answer to (2x+3}{x+2}=\frac{3x+2)/x ?

The answer to (2x+3}{x+2}=\frac{3x+2)/x is x=-1,x=-4

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(2x+3}{x+2}=\frac{3x+2)/x

\frac{2 x + 3}{x + 2} = \frac{3 x + 2}{x}

x = - 1, x = - 4

Solution steps

\frac{2 x + 3}{x + 2} = \frac{3 x + 2}{x}

Cross multiply

(2 x + 3) x = (x + 2) (3 x + 2)

Solve

(2 x + 3) x = (x + 2) (3 x + 2) : x = - 1, x = - 4

x = - 1, x = - 4

Verify Solutions

Find undefined (singularity) points:

x = - 2, x = 0

Combine undefined points with solutions:

x = - 1, x = - 4

x^{2} - 2 x - 1 = \frac{1}{2 x - 3}

\frac{x ^{3} - 4 x + 3}{x ^{4} + 2 x - 4} = 0

\frac{x}{3} - \frac{6}{x} = 1

\frac{1}{15} + \frac{1}{21} = \frac{1}{x}

\frac{x + 1}{x} = 5

What is the answer to (2x+3}{x+2}=\frac{3x+2)/x ?
The answer to (2x+3}{x+2}=\frac{3x+2)/x is x=-1,x=-4
Solve for x: (2x+3}{x+2}=\frac{3x+2)/x
The solution is x=-1,x=-4