What is the answer to 1+5/(x-1)=(3x+7)/(x^2-1) ?

The answer to 1+5/(x-1)=(3x+7)/(x^2-1) is x=-3

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1+5/(x-1)=(3x+7)/(x^2-1)

1 + \frac{5}{x - 1} = \frac{3 x + 7}{x ^{2} - 1}

x = - 3

Solution steps

1 + \frac{5}{x - 1} = \frac{3 x + 7}{x ^{2} - 1}

Multiply by LCM

(x - 1) (x + 1) + 5 (x + 1) = 3 x + 7

Solve

(x - 1) (x + 1) + 5 (x + 1) = 3 x + 7 : x = 1, x = - 3

x = 1, x = - 3

Verify Solutions

Find undefined (singularity) points:

x = 1, x = - 1

Since the equation is undefined for:

1

x = - 3

\frac{x}{x - 8} - \frac{2}{8 - x} = 2

x^{3} - x^{2} - \frac{8}{x ^{3} - x ^{2}} = 2

\frac{3}{x - 6} = \frac{2}{2 x - 9}

1 - \frac{7}{x - 2} = \frac{7}{x ^{2} - 5 x + 6}

\frac{0.3}{4} = \frac{9}{y}

What is the answer to 1+5/(x-1)=(3x+7)/(x^2-1) ?
The answer to 1+5/(x-1)=(3x+7)/(x^2-1) is x=-3
Solve for x: 1+5/(x-1)=(3x+7)/(x^2-1)
The solution is x=-3