What is the answer to 1/x+1/(x+1)= 1/(x+2) ?

The answer to 1/x+1/(x+1)= 1/(x+2) is x=-2+sqrt(2),x=-2-sqrt(2)

Solve for x: 1/x+1/(x+1)= 1/(x+2)

The solution is x=-2+sqrt(2),x=-2-sqrt(2)

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\frac{1}{x} + \frac{1}{x + 1} = \frac{1}{x + 2}

x = - 2 + 2, x = - 2 - 2

Decimal Notation

x = - 0.58578 \dots, x = - 3.41421 \dots

Solution steps

\frac{1}{x} + \frac{1}{x + 1} = \frac{1}{x + 2}

Multiply by LCM

(x + 1) (x + 2) + x (x + 2) = x (x + 1)

Solve

(x + 1) (x + 2) + x (x + 2) = x (x + 1) : x = - 2 + 2, x = - 2 - 2

x = - 2 + 2, x = - 2 - 2

Verify Solutions

Find undefined (singularity) points:

x = - 1, x = 0, x = - 2

Combine undefined points with solutions:

x = - 2 + 2, x = - 2 - 2

\frac{7}{x - 4} - \frac{6}{x - 2} = 2

\frac{x ^{2} + 3 x - 18}{6 x} = \frac{2 - 3 x}{3}

t, y = \frac{t - a}{t + 3}

2 x - \frac{1}{x} - 1 = 0

y, \frac{3}{3 x + y} = 1

What is the answer to 1/x+1/(x+1)= 1/(x+2) ?
The answer to 1/x+1/(x+1)= 1/(x+2) is x=-2+sqrt(2),x=-2-sqrt(2)
Solve for x: 1/x+1/(x+1)= 1/(x+2)
The solution is x=-2+sqrt(2),x=-2-sqrt(2)