What is the answer to (2x^2-x)/3-4= 3/x ?

The answer to (2x^2-x)/3-4= 3/x is x=-1,x=-3/2 ,x=3

Solve for x: (2x^2-x)/3-4= 3/x

The solution is x=-1,x=-3/2 ,x=3

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\frac{2 x ^{2} - x}{3} - 4 = \frac{3}{x}

x = - 1, x = - \frac{3}{2}, x = 3

Decimal Notation

x = - 1, x = - 1.5, x = 3

Solution steps

\frac{2 x ^{2} - x}{3} - 4 = \frac{3}{x}

Multiply by LCM

x (2 x^{2} - x) - 12 x = 9

Solve

x (2 x^{2} - x) - 12 x = 9 : x = - 1, x = - \frac{3}{2}, x = 3

x = - 1, x = - \frac{3}{2}, x = 3

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = - 1, x = - \frac{3}{2}, x = 3

x, y = x^{- 2}

\frac{9}{x + 1} - \frac{1}{2} = \frac{6}{3 x + 3}

y, \frac{3 x + 9 y}{5 x + 6 y} = \frac{21}{17}

20 x - \frac{90}{x ^{2}} = 0

\frac{2 x - 3}{x - 6} = \frac{3 x - 1}{x - 2}

What is the answer to (2x^2-x)/3-4= 3/x ?
The answer to (2x^2-x)/3-4= 3/x is x=-1,x=-3/2 ,x=3
Solve for x: (2x^2-x)/3-4= 3/x
The solution is x=-1,x=-3/2 ,x=3