What is the answer to solvefor x,y=x^{-2} ?

The answer to solvefor x,y=x^{-2} is x= 1/(sqrt(y)),x=-1/(sqrt(y));\quad y\ne 0

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solvefor x,y=x^{-2}

solve for

x, y = x^{- 2}

x = \frac{1}{y}, x = - \frac{1}{y}; y \neq = 0

Solution steps

y = x^{- 2}

Refine

y = \frac{1}{x ^{2}}

Multiply both sides by

x^{2}

y x^{2} = 1

Solve

y x^{2} = 1 : x = \frac{1}{y}, x = - \frac{1}{y}; y \neq = 0

x = \frac{1}{y}, x = - \frac{1}{y}; y \neq = 0

\frac{9}{x + 1} - \frac{1}{2} = \frac{6}{3 x + 3}

y, \frac{3 x + 9 y}{5 x + 6 y} = \frac{21}{17}

20 x - \frac{90}{x ^{2}} = 0

\frac{2 x - 3}{x - 6} = \frac{3 x - 1}{x - 2}

0 = \frac{2 x - 1}{x ^{2} - 4}

What is the answer to solvefor x,y=x^{-2} ?
The answer to solvefor x,y=x^{-2} is x= 1/(sqrt(y)),x=-1/(sqrt(y));\quad y\ne 0